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d/(dx)[sin {2 cos^(-1) (sin x)}]=...

`d/(dx)[sin {2 cos^(-1) (sin x)}]`=

A

`-2 sin 2x`

B

`-2 cos 2x`

C

2 sin 2x

D

2 cos 2x

Text Solution

Verified by Experts

The correct Answer is:
D
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