If y=(sinx)^(tanx),then(dy)/(dx) is equa...

If `y=(sinx)^(tanx),then(dy)/(dx)` is equal to

A

`(sinx)^(tanx).[1+sec^2x.log(sinx)]`

B

`tanx.(sinx)^(tanx-1).cosx`

C

`(sinx)^(tanx).sec^2.x.log(sinx)`

D

`tanx.(sinx)^(tanx-1)`

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The correct Answer is:

A

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