if 2x^2-3xy+y^2+x+2y-8=0 then (dy)/(dx)...

if `2x^2-3xy+y^2+x+2y-8=0` then `(dy)/(dx)`

A

`(3y-4x-1)/(2y-3x+2)`

B

`(3y+4x+1)/(2y+3x+2)`

C

`(3y-4x-1)/(2y-3x-2)`

D

`(3y-4x+1)/(2y+3x+2)`

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Verified by Experts

The correct Answer is:

A

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