If x=acostheta,y=bsintheta , then (d^2y)...

If `x=acostheta,y=bsintheta` , then `(d^2y)/(dx^2)` when `theta=pi/4` is given by

A

`-2sqrt2b/a^2`

B

`2sqrt2b/a^2`

C

`(sqrt2a^2)/b`

D

`(2a^2)/b`

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The correct Answer is:

A

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