If p=a^2cos^2theta+b^2 sin^2 theta, wher...

If `p=a^2cos^2theta+b^2 sin^2 theta`, where `a^2+b^2=c^2` ,
then `4p+(d^2p)/(d theta^2)` is equal to

A

`c^2`

B

`2c^2`

C

`4c^2`

D

`8c^2`

Verified by Experts

The correct Answer is:

B

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