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An electric heater of 1200 W is operated...

An electric heater of 1200 W is operated for 3 hrs daily. What will be the electrical consumption expenses for that in the month of June ? (The electric company charges Rs 5 per unit of energy.)

Text Solution

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Here, power `=1200W=1.2xx10^(3)W=1.2kW`
`"Time "="3 hrs daily for 30 days …[month of June consist of 30 days]"`
`=3xx30="90 hours"`
`therefore" Energy consumed "="power"xx"time"=1.2xx90="108 kWh"`
`therefore" Electrical energy expenses "="Energy consumed "xx"charges per unit"`
`=108xx5`
`"Rs 540"`
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