During `G_(2)` -phase a diploid cell contains the amount of DNA equal to a :-

Options

A. 4n
B. 8n
C. 2n
D. 1n

Answer

To solve the question regarding the amount of DNA present in a diploid cell during the G2 phase, we can break down the process into clear steps:

### Step-by-Step Solution:

1. **Understanding the Cell Cycle**:
- The cell cycle consists of several phases: G1, S, G2, and M (mitosis). Each phase has specific functions and roles in cell growth and division.

2. **Identifying the G1 Phase**:
- In the G1 phase, the cell grows and synthesizes mRNA and proteins necessary for DNA synthesis. At this stage, a diploid cell contains a diploid amount of DNA, denoted as 2n.

3. **Transition to the S Phase**:
- After G1, the cell enters the S phase (Synthesis phase). This is where DNA replication occurs. Each chromosome is duplicated, resulting in two identical sister chromatids for each chromosome.

4. **Understanding DNA Content After S Phase**:
- At the end of the S phase, the amount of DNA in the cell doubles. Therefore, if the diploid cell originally had 2n amount of DNA, after the S phase, it will have 4n (since each chromosome has been replicated).

5. **Moving to the G2 Phase**:
- The G2 phase follows the S phase. During G2, the cell prepares for division, and the DNA content remains at 4n because the chromosomes are still in their duplicated state (as sister chromatids).

6. **Conclusion**:
- Therefore, during the G2 phase, a diploid cell contains an amount of DNA equal to 4n.

### Final Answer:
During the G2 phase, a diploid cell contains the amount of DNA equal to **4n**.

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