If a somatic cell undergoes two successive nuclear divisions without cytokinesis, the resultant structure will have

Options

A. 2 diploid nuclei
B. 4 diploid nuclei
C. 4 haploid nuclei
D. 2 haploid nuclei

Answer

To solve the question about the outcome of a somatic cell undergoing two successive nuclear divisions without cytokinesis, we can break down the process step by step:

### Step-by-Step Solution:

1. **Understanding Somatic Cells**:
- Somatic cells are body cells that are diploid (2n), meaning they contain two sets of chromosomes (one from each parent).

2. **First Nuclear Division (Mitosis)**:
- When a diploid somatic cell undergoes its first nuclear division (mitosis), it divides its nucleus into two nuclei, each still diploid (2n).
- At this point, we have two diploid nuclei (2n, 2n).

3. **Second Nuclear Division (Mitosis)**:
- If the cell undergoes a second nuclear division without cytokinesis, each of the two diploid nuclei will again divide.
- This results in four diploid nuclei (2n, 2n, 2n, 2n).

4. **Final Structure**:
- Since cytokinesis did not occur, all four nuclei remain within the same cell, leading to a structure with four diploid nuclei.

### Conclusion:
The resultant structure after two successive nuclear divisions without cytokinesis will have **four diploid nuclei**.

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