At the time of conduction of nerve impulse, the repolarization occurs with me

Options

A. Efflux of `K^(+)` ions
B. Influx of `K^(+)` ions
C. Efflux of `Na^(+)` ions
D. Efflux of both `Na^(+) and K^(+)` ions

Answer

### Step-by-Step Solution

1. **Understanding Nerve Impulse Conduction**:
- Nerve impulses are conducted through neurons, which undergo changes in membrane potential.

2. **Resting Membrane Potential**:
- The neuron is typically at a resting membrane potential of approximately -70 mV.

3. **Depolarization Phase**:
- When a stimulus reaches the neuron, sodium channels open, allowing sodium ions (Na⁺) to enter the neuron (influx).
- This influx of sodium ions causes the membrane potential to rise from -70 mV to about +40 mV.

4. **Repolarization Phase**:
- After depolarization, the sodium channels close, and potassium channels open.
- Potassium ions (K⁺) move out of the neuron (efflux), which causes the membrane potential to decrease back towards the resting state.

5. **Conclusion**:
- During the repolarization phase of nerve impulse conduction, the key process is the efflux of potassium ions. This movement helps restore the negative membrane potential after depolarization.

### Final Answer:
At the time of conduction of a nerve impulse, the repolarization occurs with the **efflux of potassium ions**.

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