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in the process of repiration in plants 1...

in the process of repiration in plants 180 gms of sugar plus 192 gms of oxygen produce

A

`132gCO_2+54gH_2O+337k` cal

B

`264 g CO_2+108gH_2O+686 k` cal

C

528 g `CO_2` + 216 g water+ 686 kcal

D

Large amount of `CO_2` and energy

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The correct Answer is:
To solve the problem of what is produced from the respiration of 180 grams of sugar (glucose) and 192 grams of oxygen, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - We have 180 grams of glucose (C6H12O6) and 192 grams of oxygen (O2). 2. **Calculate Moles of Glucose**: - The molecular weight of glucose (C6H12O6) is calculated as follows: - Carbon (C): 12 g/mol × 6 = 72 g/mol - Hydrogen (H): 1 g/mol × 12 = 12 g/mol - Oxygen (O): 16 g/mol × 6 = 96 g/mol - Total molecular weight of glucose = 72 + 12 + 96 = 180 g/mol - Now, using the formula for moles: \[ \text{Number of moles of glucose} = \frac{\text{Weight in grams}}{\text{Molecular weight}} = \frac{180 \text{ g}}{180 \text{ g/mol}} = 1 \text{ mole} \] 3. **Calculate Moles of Oxygen**: - The molecular weight of oxygen (O2) is: - Oxygen (O): 16 g/mol × 2 = 32 g/mol - Now, using the formula for moles: \[ \text{Number of moles of oxygen} = \frac{192 \text{ g}}{32 \text{ g/mol}} = 6 \text{ moles} \] 4. **Write the Respiration Equation**: - The balanced equation for the respiration of glucose is: \[ C6H12O6 + 6 O2 \rightarrow 6 CO2 + 6 H2O + 686 \text{ kcal} \] - From the equation, 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water. 5. **Calculate the Mass of Products**: - **Mass of Carbon Dioxide (CO2)**: - Molecular weight of CO2 = 12 (C) + 16×2 (O) = 44 g/mol - Mass from 6 moles = 6 moles × 44 g/mol = 264 g - **Mass of Water (H2O)**: - Molecular weight of H2O = 1×2 (H) + 16 (O) = 18 g/mol - Mass from 6 moles = 6 moles × 18 g/mol = 108 g 6. **Summarize the Products**: - The products of the reaction are: - 264 grams of carbon dioxide (CO2) - 108 grams of water (H2O) - 686 kilocalories of energy ### Final Answer: The products produced from the respiration of 180 grams of sugar and 192 grams of oxygen are: - 264 grams of carbon dioxide (CO2) - 108 grams of water (H2O) - 686 kilocalories of energy
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TRUEMEN BIOLOGY ENGLISH-RESPIRATION IN PLANTS-MULTIPLE CHOICE QUESTIONS
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  2. in the process of repiration in plants 180 gms of sugar plus 192 gms o...

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  3. When respiratory substrate is fat, respiration Is called

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  4. The efficiency of respiration is approximately

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  5. Glyceraldehyde phosphate is oxidised in glycolysis. What is the fate o...

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  6. In the formation of Acetyl Co-A from pyruvic acid in mitochondria, pyr...

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  7. When a yeast produces wine, which is not formed ?

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  8. The net gain of glycolysis of one molecule of glucose is the formation...

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  9. During photosynthesis oxygen in glucose comes from

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  10. How many oxygen molecules are used in glycolysis of one molecule of gl...

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  11. Link between glycolysis, Krebs cycle and beta-oxidation of fatty acid ...

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  12. When yeast ferments glucose, the products are:

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  13. Energy required to form glucose from pyruvate is equivalent to

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  14. Which is formed through phosphorylation in glycolysis?

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  15. Which step of glycolysis requires pyruvic kinase, Mg^(++),K^(+) and AD...

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  16. One molecule of glucose requires 2 ATP to get phosphorylated to form F...

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  17. Amphibolic cycle that occurs only in aerobic condition is

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  18. During respiration, pyruvic acid is

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  19. Krebs' cycle starts with the formation of a six carbon compound by rea...

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  20. Aerobic glycolysis is times efficient than anaerobic glycolysis

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