The net gain of glycolysis of one molecule of glucose is the formation of

Options

A. 2NADH + `H^+` + 4ATP+ 1 Pyruvic acid
B. 2NADH + `H^+` + 2ATP+2 Pyruvic acid
C. SATP +2NADH + `H^+` +2 Pyruvic acid
D. SATP+2NADH+`H^+`+ 2 Pyruvic acid +`CO_2`

Answer

**Step-by-Step Solution:**

1. **Understanding Glycolysis:**
- Glycolysis is a metabolic pathway that breaks down glucose (C6H12O6) into pyruvate, producing energy in the form of ATP.

2. **Chemical Reaction of Glycolysis:**
- The overall reaction of glycolysis involves converting one molecule of glucose into two molecules of pyruvate and water.
- The simplified equation can be represented as:
\[ C6H12O6 \rightarrow 2 \text{Pyruvate} + 2 \text{H2O} \]

3. **ATP Production:**
- During glycolysis, a total of 4 ATP molecules are produced. However, 2 ATP molecules are consumed in the initial steps of the pathway to prepare glucose for breakdown.
- Therefore, the net gain of ATP is:
\[ 4 \text{ ATP (produced)} - 2 \text{ ATP (used)} = 2 \text{ ATP} \]

4. **NADH Production:**
- Glycolysis also involves the reduction of NAD+ to NADH. For every glucose molecule, 2 NADH molecules are produced.
- The reaction can be summarized as:
\[ 2 \text{NAD}^+ + 4 \text{e}^- + 4 \text{H} \rightarrow 2 \text{NADH} + 2 \text{H}^+ \]

5. **Final Products of Glycolysis:**
- Therefore, the net gain from one molecule of glucose during glycolysis is:
- 2 molecules of pyruvate
- 2 molecules of ATP
- 2 molecules of NADH

6. **Conclusion:**
- The net gain of glycolysis from one molecule of glucose is the formation of:
- 2 Pyruvate
- 2 ATP
- 2 NADH

**Final Answer:**
The net gain of glycolysis of one molecule of glucose is the formation of 2 pyruvate, 2 ATP, and 2 NADH.

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