Oxidation of one molecule of glucose yields 38 mols of ATP in the proportion of

Options

A. all the 38 mols in mitochondrion
B. 8 outside mitochondrion and 30 inside mitochondrion
C. two glycolysis and 36 inside the Kreb cycle
D. two outside and 36 inside the mitochondrion

Answer

To solve the question regarding the oxidation of one molecule of glucose yielding 38 moles of ATP in the specified proportions, we can break down the process as follows:

### Step-by-Step Solution:

1. **Understanding Glycolysis**:
- Glycolysis occurs in the cytoplasm of the cell and is the first step in glucose metabolism.
- During glycolysis, one molecule of glucose is converted into two molecules of pyruvate, yielding a net gain of **2 ATP** and **2 NADH**.

2. **Decarboxylation**:
- After glycolysis, the pyruvate enters the mitochondria where it undergoes decarboxylation.
- This process produces **2 NADH** from the conversion of pyruvate to acetyl-CoA, but does not produce ATP directly.

3. **Citric Acid Cycle (Krebs Cycle)**:
- The acetyl-CoA then enters the citric acid cycle, which also occurs in the mitochondria.
- For each acetyl-CoA that enters the cycle, the following products are generated:
- **3 NADH**
- **1 FADH2**
- **1 GTP (which can be converted to ATP)**
- Since each glucose molecule produces two acetyl-CoA molecules, the total yield from the citric acid cycle is:
- **6 NADH** (3 NADH x 2)
- **2 FADH2** (1 FADH2 x 2)
- **2 GTP (or ATP)**

4. **Total ATP Calculation**:
- Now, we can summarize the ATP yield:
- From glycolysis: **2 ATP**
- From decarboxylation: **0 ATP** (but 2 NADH)
- From the citric acid cycle: **2 ATP (GTP)** + **6 NADH** + **2 FADH2**
- The NADH and FADH2 produced in the mitochondria will contribute to ATP production via oxidative phosphorylation:
- Each NADH can yield approximately **2.5 ATP** (total from glycolysis and Krebs cycle: 10 NADH).
- Each FADH2 can yield approximately **1.5 ATP** (total from Krebs cycle: 4 FADH2).

5. **Final ATP Yield**:
- Total from glycolysis: **2 ATP** (directly) + **2 NADH** (which yield 5 ATP) = **7 ATP**
- Total from decarboxylation: **0 ATP** + **2 NADH** (which yield 5 ATP) = **5 ATP**
- Total from Krebs cycle: **2 ATP** + **6 NADH** (which yield 15 ATP) + **2 FADH2** (which yield 3 ATP) = **20 ATP**
- Adding these together gives: **7 + 5 + 20 = 32 ATP**.

6. **Correct Proportions**:
- The total ATP yield from one glucose molecule is **38 ATP**, with **8 ATP produced outside the mitochondria (from glycolysis)** and **30 ATP produced inside the mitochondria (from the citric acid cycle and oxidative phosphorylation)**.

### Conclusion:
The correct answer to the question is **8 outside the mitochondria and 30 inside the mitochondria**.