A mass of living cells are kept in a culture medium under anaerobic conditions. The cells were supplied with labelled `c^14` glucose. Pick up the true statement

Options

A. `CO_2` will contain `C^14`
B. cell would burst
C. water will have radioactivity
D. ATP will have radioactivity

Answer

To solve the question regarding the behavior of living cells under anaerobic conditions when supplied with labeled C-14 glucose, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Anaerobic Conditions**:
- Anaerobic conditions mean that there is no oxygen available for the cells. Under these conditions, cells typically undergo fermentation instead of aerobic respiration.

2. **Identify the Substrate**:
- The cells are supplied with C-14 labeled glucose (C6H12O6). This means that the glucose molecule contains a radioactive carbon isotope, C-14.

3. **Fermentation Process**:
- In the absence of oxygen, glucose is broken down through fermentation. In many organisms, this process results in the production of ethanol (C2H5OH) and carbon dioxide (CO2).

4. **Products of Fermentation**:
- The fermentation of one molecule of glucose will yield:
- 2 molecules of ethanol (C2H5OH)
- 2 molecules of carbon dioxide (CO2)

5. **Radioactivity in Products**:
- Since the original glucose molecule contained C-14, the carbon atoms in the resulting ethanol and carbon dioxide will also contain C-14. Therefore, both ethanol and carbon dioxide produced will be radioactive.

6. **Evaluate the Statements**:
- **Statement 1**: Carbon dioxide will contain C-14. (True)
- **Statement 2**: The cell would burst. (False; cells typically do not burst under fermentation conditions.)
- **Statement 3**: Water will have radioactivity. (False; water does not contain carbon.)
- **Statement 4**: ATP will have radioactivity. (False; ATP does not contain carbon from glucose.)

7. **Conclusion**:
- The true statement is that carbon dioxide will contain C-14.

### Final Answer:
The correct answer is: **Carbon dioxide will contain C-14.**

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