The number of glucose molecules required to produce 38 ATP molecules under anaerobic conditions by a yeast cells is

Options

A. (a) 2
B. (b) 1
C. (c) 19
D. (d) 38

Answer

To determine the number of glucose molecules required to produce 38 ATP molecules under anaerobic conditions in yeast cells, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Anaerobic Respiration in Yeast**:
- Yeast cells perform alcoholic fermentation in the absence of oxygen. During this process, glucose is converted into ethanol and carbon dioxide, while producing ATP.

2. **ATP Production from One Glucose Molecule**:
- In the anaerobic process, one molecule of glucose is converted into two molecules of pyruvate, and in the process, 2 ATP molecules are produced.
- The reaction can be summarized as:
- Glucose → 2 Pyruvate + 2 ATP

3. **Calculating ATP Production**:
- Since each glucose molecule yields 2 ATP, we need to find out how many glucose molecules are required to produce 38 ATP.
- To find this, we can set up a simple equation:
- If 1 glucose = 2 ATP, then to find the number of glucose molecules (let's call it 'x') needed for 38 ATP, we can use the formula:
\[ 2x = 38 \]

4. **Solving for x**:
- Dividing both sides of the equation by 2 gives:
\[ x = \frac{38}{2} = 19 \]

5. **Conclusion**:
- Therefore, 19 glucose molecules are required to produce 38 ATP molecules under anaerobic conditions in yeast cells.

### Final Answer:
The number of glucose molecules required to produce 38 ATP molecules under anaerobic conditions by yeast cells is **19**.

---