One mole of glucose on complete oxidation in aerobic respiration yields ?

Options

A. 2870 KJ
B. 5000 KJ
C. 686 KJ
D. 1870 KJ

Answer

To solve the question regarding the energy yield from the complete oxidation of one mole of glucose in aerobic respiration, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Process**: Recognize that aerobic respiration involves the complete oxidation of glucose (C6H12O6) in the presence of oxygen, producing carbon dioxide (CO2) and water (H2O).

2. **Energy Yield from Glucose**: It is known that the complete oxidation of one mole of glucose releases approximately 686 kilocalories of energy.

3. **Convert Kilocalories to Kilojoules**: Since the question asks for the energy yield in kilojoules, we need to convert kilocalories to kilojoules. The conversion factor is:
\[ 1 \text{ kilocalorie} = 4.184 \text{ kilojoules} \]

4. **Calculate the Total Energy in Kilojoules**:
\[ \text{Energy in kilojoules} = 686 \text{ kilocalories} \times 4.184 \text{ kilojoules/kilocalorie} \]
\[ = 2870.784 \text{ kilojoules} \]

5. **Round the Result**: For practical purposes, we can round this to 2870 kilojoules.

6. **Final Answer**: Therefore, one mole of glucose on complete oxidation in aerobic respiration yields approximately **2870 kilojoules**.