Home
Class 12
BIOLOGY
The simple phenomenon of shrinkage of th...

The simple phenomenon of shrinkage of the protoplasm from the cell wall under the action of some strong solution ( than that of the cell sap ) is due to decrease in

A

root pressure

B

turgor pressure

C

DPD

D

osmotic pressure

Text Solution

AI Generated Solution

The correct Answer is:
**Step-by-Step Solution:** 1. **Understanding the Context**: The question describes a phenomenon where the protoplasm shrinks away from the cell wall when a plant cell is placed in a solution that has a higher concentration of solutes compared to the cell sap. This situation typically occurs in a hypertonic solution. 2. **Identifying the Type of Solution**: A hypertonic solution has a higher concentration of solutes than the cell sap. When a cell is placed in such a solution, water moves out of the cell to balance the concentration of solutes. 3. **Movement of Water**: Due to osmosis, water will move from an area of lower solute concentration (inside the cell) to an area of higher solute concentration (the surrounding solution). This results in a loss of water from the cell. 4. **Effect on the Cell**: As water leaves the cell, the volume of the protoplasm decreases, leading to the shrinkage of the protoplasm away from the cell wall. This phenomenon is known as plasmolysis. 5. **Role of Turgor Pressure**: Turgor pressure is the pressure exerted by the fluid (in this case, water) inside the cell against the cell wall. When water leaves the cell, the turgor pressure decreases. This decrease in turgor pressure is what causes the protoplasm to shrink away from the cell wall. 6. **Conclusion**: The shrinkage of the protoplasm from the cell wall is primarily due to the decrease in turgor pressure. Therefore, the correct answer to the question is "turgor pressure." **Final Answer**: The shrinkage of the protoplasm from the cell wall under the action of a strong solution is due to a decrease in turgor pressure. ---
Promotional Banner

Topper's Solved these Questions

  • THE LIVING WORLD

    TRUEMEN BIOLOGY ENGLISH|Exercise MULTIPLE CHOICE QUESTIONS|119 Videos
  • Viruses

    TRUEMEN BIOLOGY ENGLISH|Exercise ASSERTION AND REASON|21 Videos

Similar Questions

Explore conceptually related problems

Water will enter a cell if it is placed in solution less concentrated than cell sap due to

Assertion : Shrinkage of the protoplast of a cell occurs under the influence of hypertonic solution. Reason : Hypertonic solution causes plasmolysis.

The external solution having same concentration than the cell sap is called

A candidate in order to study the process of osmosis has taken 3 potato cubes and put them in 3 different beakers containing 3 different solutions. After 24 hours, in the first beaker, the potato cube increased in size, in the second beaker, the potato cube decreased in size and in the third beaker there was no change in the size of the potato cube. The following diagram shows the result of the same experiment : Write the specific feature of the cell sap of root hairs which helps in absorption of water.

Name the following : Loss of cell sap through hydathodes from the tip or margin of leaf is due to root pressure.

The opening of the stomata is also aided due to the orientation of the microfibrils in the cell walls of the guard cells. Cellulose microfibrils are oriented_ rather than making it easier for the stoma to open.

Find out the correct pair of statements (i) In completely plasmolysed cell, pressure potential does not contribute to water potential (ii) If a cell is placed in hypotonic solution for longer time , the cell membrane shrinks away from its cell wall (iii) Apoplastic system comprises interconected protoplasts (iv) Polypeptides have more imbibing capacity then polysaccharides

A solution of H_(2)O_(2) labelled as '20 V' was left open. Due to this some, H_(2)O_(2) decomposed and volume strength of the solution decreased . To determine the new volume strength of the H_(2)O_(2) solution, 10 mL of the solution was taken and it was diluted to 100 mL . 10 mL of this diluted solution was titrated against 25 mL of 0.0245 M KMnO_(4) solution under acidic condition. Calculate the volume strength of the H_(2)O_(2) solution .

How many of the following statement(s) is/are true regarding plant water relations? A. A mature corn plant absorbs almost three litres of water in three hours only while a mustard plant absorbs water equal to its own weight in about five hours. B.Diffusion is a slow process and is dependent on a 'living system'. C.When a plant cell is placed in a hypertonic solution, water moves out first from the cytoplasm and then from the vacuole. D. All solutions have a higher water potential than pure water due to dissolution of solutes.

A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system.A liquid vapourises to form a more disordered gas.When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness.As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas.Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendency to freeze.In consequence, a lower the temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution.Elevation of B.Pt.(DeltaT_b) and depression of F.Pt.(DeltaT_f) of a solution are the colligative properties which depend only on the concentration of particles of the solute, not their identify.For dilute solutions. DeltaT_b and DeltaT_f are proportional to the molality of the solute in the solution. DeltaT_b=K_bm , K_b =Ebullioscopic constant= (RT_(b)^(@^(2))M)/(1000 DeltaH_(vap)) And DeltaT_f=K_fm , K_f =Cryoscopic constant= (RT_(f)^(@^(2))M)/(1000 DeltaH_(fus)) (M=molecular mass of the sovent) The values of K_b and K_f do depend on the properties of the solvent.For liquids, (DeltaH_(vap))/T_b^@ is almost constant. [Troutan's Rule, this constant for most of the unassociated liquids (not having any strong bonding like Hydrogen bonding in the liquid state ) is equal to 90 J//"mol" .] For solutes undergoing changes of molecular state is solution (ionization or association), the observed DeltaT values differ from the calculated ones using the above relations In such situations, the relationships are modified as DeltaT_b=i K_bm, DeltaT_f=i K_fm where i=Van't Hoff factor, greater than unity for ionization and smaller than unity for association of the solute molecules. A mixture of two Immiscible liquids at a constant pressure of 1 atm boils at a temperature

TRUEMEN BIOLOGY ENGLISH-TRANSPORT IN PLANTS-Multiple Choice Questions
  1. The value of osmotic pressure becomes equal to turgor pressure when a ...

    Text Solution

    |

  2. The value of osmotic pressure becomes equal to diffusion pressure defi...

    Text Solution

    |

  3. The simple phenomenon of shrinkage of the protoplasm from the cell wa...

    Text Solution

    |

  4. The diffusion pressure deficit of a cell protoplasm is equal to

    Text Solution

    |

  5. The osmotic pressure of pure and clean water is

    Text Solution

    |

  6. Which of the following has the higher water potential ?

    Text Solution

    |

  7. During absorption of water by roots , the water potential of cell sap ...

    Text Solution

    |

  8. An osmotically active substance is that which can

    Text Solution

    |

  9. The relationship of DPD , OP , TP and WP is

    Text Solution

    |

  10. A cell is plasmolysed after being kept in hypertonic solution . What w...

    Text Solution

    |

  11. The potential energy of water is referred to as

    Text Solution

    |

  12. Addition of a solute to pure water causes

    Text Solution

    |

  13. Water potential and osmotic potential of pure water are

    Text Solution

    |

  14. What would be Psi(P) in cell A and cell B respectively ?

    Text Solution

    |

  15. Cell A has osmotic potential of -18 bars and pressure potential of 8 b...

    Text Solution

    |

  16. If a cell loses water its D.P.D.

    Text Solution

    |

  17. A cell 'A' has Psi(W)=-18 bars and its adjacent cell 'B' has a water p...

    Text Solution

    |

  18. Water potential of a solution is always

    Text Solution

    |

  19. When the cell is turgid

    Text Solution

    |

  20. Reduction of water potential due to presence of solute is

    Text Solution

    |