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A population will not exist in Hardly-We...

A population will not exist in Hardly-Weinberg equilbrium if

A

there are no mutation

B

there is no migration

C

the population is large

D

individuals mate selectively

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The correct Answer is:
### Step-by-Step Solution: 1. **Understanding Hardy-Weinberg Equilibrium**: The Hardy-Weinberg principle states that allele frequencies in a population will remain constant from generation to generation in the absence of evolutionary influences. This is known as genetic equilibrium. 2. **Conditions for Hardy-Weinberg Equilibrium**: There are five main conditions that must be met for a population to be in Hardy-Weinberg equilibrium: - No mutations - Random mating - No gene flow (migration) - Large population size (to prevent genetic drift) - No natural selection 3. **Identifying Factors that Disrupt Equilibrium**: A population will not exist in Hardy-Weinberg equilibrium if any of the above conditions are violated. Specifically, if there is: - **Mutation**: Changes in the genetic material can alter allele frequencies. - **Non-random mating**: If individuals select mates based on certain traits, this can affect allele frequencies. - **Migration**: Movement of individuals into or out of the population can introduce new alleles or remove existing ones. - **Small population size**: In smaller populations, random events can have a larger impact on allele frequencies (genetic drift). - **Natural selection**: If certain traits confer a survival advantage, those alleles will increase in frequency over time. 4. **Conclusion**: Based on the conditions listed, the population will not exist in Hardy-Weinberg equilibrium if individuals mate selectively. This violates the condition of random mating, which is essential for maintaining constant allele frequencies. ### Final Answer: A population will not exist in Hardy-Weinberg equilibrium if individuals mate selectively. ---
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