`CH_(3)(CH_(2))_(7)CH =CH(CH_(2))_(7).COOH` is

Options

A. oxalousuccinate
B. oleic acid
C. linolenic acids
D. `alpha`-ketoglutarate

Answer

To determine the identity of the compound represented by the formula `CH₃(CH₂)₇CH=CH(CH₂)₇COOH`, we can follow these steps:

### Step 1: Analyze the Structure
The given formula can be broken down as follows:
- The `CH₃` at the beginning indicates a methyl group.
- The `(CH₂)₇` indicates a long carbon chain with 7 methylene groups.
- The `CH=CH` indicates a double bond between two carbon atoms.
- The `(CH₂)₇` following the double bond indicates another chain of 7 methylene groups.
- The `COOH` at the end indicates a carboxylic acid functional group.

### Step 2: Count the Carbon Atoms
Let's count the total number of carbon atoms in the structure:
- From `CH₃`: 1 carbon
- From `(CH₂)₇`: 7 carbons
- From `CH=CH`: 2 carbons
- From the second `(CH₂)₇`: 7 carbons
- From `COOH`: 1 carbon

Total = 1 + 7 + 2 + 7 + 1 = 18 carbons

### Step 3: Identify the Functional Groups
The presence of the `COOH` group indicates that this compound is a fatty acid. Additionally, the `CH=CH` indicates that it has a double bond, which classifies it as an unsaturated fatty acid.

### Step 4: Determine the Type of Fatty Acid
Since there is one double bond, this fatty acid is classified as monounsaturated. The position of the double bond is at the 9th carbon from the carboxylic acid end, which is characteristic of oleic acid.

### Step 5: Conclusion
Based on the analysis, the compound `CH₃(CH₂)₇CH=CH(CH₂)₇COOH` is identified as oleic acid.

### Final Answer
The correct option is **B: Oleic Acid**.

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