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In a diluated starch solution , alpha-sa...

In a diluated starch solution , `alpha`-salivary amylase is added at ph 1.6 and kept at `35^(@)C` for half an hour and then iodine solution is added, what would be the result?

A

There will be a red colour

B

There will be bule solution

C

Solution will be clear and colourless

D

The solution will be sweet

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the effects of adding alpha-salivary amylase to a diluted starch solution at a low pH and a specific temperature, followed by the addition of iodine solution. ### Step-by-Step Solution: 1. **Understanding the Components**: - **Starch**: A polysaccharide composed of glucose units, which is the stored form of glucose in plants. - **Alpha-Salivary Amylase**: An enzyme that catalyzes the hydrolysis of starch into simpler sugars, primarily maltose and glucose. - **Iodine Solution**: A reagent that reacts with starch to produce a blue-black color. 2. **Conditions of the Experiment**: - The starch solution is diluted. - Alpha-salivary amylase is added at pH 1.6, which is quite acidic. - The solution is kept at 35°C for half an hour. 3. **Effect of pH on Amylase Activity**: - Alpha-salivary amylase is most active at a neutral pH (around 6.7 to 7.0). At pH 1.6, the enzyme is likely to be denatured or inactive, which means it cannot effectively convert starch into glucose. 4. **Result After Half an Hour**: - Since the amylase is not functioning properly due to the acidic pH, the starch will not be broken down into glucose. Therefore, the solution will still contain starch. 5. **Adding Iodine Solution**: - When iodine is added to a solution containing starch, it will react with the starch to produce a blue-black color. Since the starch remains intact, we expect to see this color change. 6. **Conclusion**: - The solution will show a blue-black color due to the presence of unreacted starch. It will not be colorless or sweet because the starch has not been converted into glucose. ### Final Answer: The result will be a blue-black color in the solution due to the presence of starch.
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