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In E. coli DNA has 18% of bases of cytos...

In E. coli DNA has 18% of bases of cytosine. What will be the fraction of adenine?

A

0.18

B

0.32

C

0.36

D

data insufficient

Text Solution

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The correct Answer is:
To solve the problem of determining the fraction of adenine in E. coli DNA given that cytosine constitutes 18% of the bases, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Chargaff's Rules**: According to Chargaff's rules, in DNA: - The amount of adenine (A) is equal to the amount of thymine (T). - The amount of guanine (G) is equal to the amount of cytosine (C). 2. **Identify Given Information**: We know that: - Cytosine (C) = 18% 3. **Calculate Guanine (G)**: Since G = C, we can conclude: - Guanine (G) = 18% 4. **Calculate Total Percentage of G and C**: - Total (G + C) = G + C = 18% + 18% = 36% 5. **Calculate Total Percentage of A and T**: - Since A + T = 100% - (G + C), we find: - A + T = 100% - 36% = 64% 6. **Determine the Fraction of Adenine (A)**: - Since A = T, we can express A as: - A + A = 64% (because A = T) - 2A = 64% - A = 64% / 2 = 32% 7. **Convert to Fraction**: - To express adenine as a fraction of the total bases, we convert the percentage to a fraction: - Fraction of adenine = 32% = 32/100 = 0.32 ### Final Answer: The fraction of adenine in E. coli DNA is **0.32**. ---
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