From a cross AABb x aaBb, the genotypes AaBB:AaBb:Aabb,aabb are obtained in ratio

Options

A. `1:1:1:1`
B. `1:2:1:0`
C. `0:3:1:0`
D. `1:1:1:0`

Explanation

To solve the problem of determining the genotypic ratio from the cross AABb x aaBb, we can follow these steps:

### Step 1: Identify the Parent Genotypes
The parent genotypes are:
- Parent 1: AABb
- Parent 2: aabb

### Step 2: Determine the Gametes
Next, we need to determine the possible gametes produced by each parent.
- Parent 1 (AABb) can produce two types of gametes: AB and Ab.
- Parent 2 (aabb) can produce one type of gamete: ab.

### Step 3: Set Up the Punnett Square
Now, we can set up a Punnett square to visualize the combinations of gametes from both parents.

```
ab
__________
AB | AaBb |
|__________|
Ab | Aabb |
|__________|
```

### Step 4: Fill in the Punnett Square
Now, we fill in the Punnett square with the combinations of the gametes:
- From AB and ab, we get AaBb.
- From Ab and ab, we get Aabb.

### Step 5: List the Offspring Genotypes
From the Punnett square, we can see the resulting genotypes:
1. AaBb
2. Aabb

### Step 6: Count the Genotypes
Now we count the occurrences of each genotype:
- AaBb: 1
- Aabb: 1

### Step 7: Determine the Genotypic Ratio
The genotypic ratio of the offspring can be summarized as:
- AaBb : Aabb = 1 : 1

### Conclusion
The genotypic ratio from the cross AABb x aaBb is 1:1.