Expected children of a blue - eyed (recessive ) woman and brown eyed (dominant ) man who had a blue eyed mother are likely to be

Options

A. all brown eyed
B. all blue eyed
C. one blue eyed and one brown eyed
D. three blue eyed and one brown eyed

Explanation

To solve the problem of the expected children of a blue-eyed (recessive) woman and a brown-eyed (dominant) man who has a blue-eyed mother, we can follow these steps:

### Step 1: Determine the Genotypes of the Parents
- The blue-eyed woman is homozygous recessive, which means her genotype is **bb** (where "b" represents the blue eye allele).
- The brown-eyed man has a blue-eyed mother, which means he must carry the recessive allele as well. Therefore, his genotype is **Bb** (where "B" represents the brown eye allele and "b" represents the blue eye allele).

### Step 2: Set Up a Punnett Square
- We will set up a Punnett square to determine the possible genotypes of their children. The alleles from the woman (bb) will be placed on one side, and the alleles from the man (Bb) will be placed on the other side.

```
B b
------------
b | Bb | bb |
------------
b | Bb | bb |
```

### Step 3: Analyze the Punnett Square
- From the Punnett square, we can see the possible genotypes of the offspring:
- **Bb** (brown-eyed) - 2 squares
- **bb** (blue-eyed) - 2 squares

### Step 4: Calculate the Ratios
- The ratio of the genotypes is:
- 2 Bb (brown-eyed) : 2 bb (blue-eyed)
- This simplifies to a ratio of 1 brown-eyed : 1 blue-eyed.

### Step 5: Conclusion
- Therefore, the expected children of the blue-eyed woman and the brown-eyed man are likely to be:
- 50% brown-eyed (Bb)
- 50% blue-eyed (bb)

### Final Answer
The expected children will be 1 brown-eyed child and 1 blue-eyed child.

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