Which one of the following individuals can produce 16 different gametes?

Options

A. Aa Bb cc Dd
B. Aa Bb cc DD Ee Ff
C. Aa Bb Cc dd EE FF
D. Aa Bb Cc DD Ee Ff

Explanation

To determine which individual can produce 16 different gametes, we will use the formula for calculating the number of gametes, which is given by \(2^n\), where \(n\) is the number of heterozygous alleles.

### Step-by-Step Solution:

1. **Understand the Formula**:
The number of different gametes that can be produced by an individual is calculated using the formula \(2^n\), where \(n\) is the number of heterozygous gene pairs.

**Hint**: Remember that heterozygous alleles are represented by two different alleles (e.g., Aa).

2. **Analyze Each Option**:
We will evaluate each option provided to find the number of heterozygous alleles.

- **Option A**: Count the heterozygous alleles.
- If there are 3 heterozygous alleles, then \(n = 3\).
- Calculate \(2^3 = 8\) gametes.

**Hint**: Look for pairs of alleles that are different (heterozygous).

- **Option B**: Count the heterozygous alleles.
- If there are 4 heterozygous alleles, then \(n = 4\).
- Calculate \(2^4 = 16\) gametes.

**Hint**: Ensure to only count heterozygous pairs.

- **Option C**: Count the heterozygous alleles.
- If there are 3 heterozygous alleles, then \(n = 3\).
- Calculate \(2^3 = 8\) gametes.

**Hint**: Repeat the counting process for each option.

- **Option D**: Count the heterozygous alleles.
- If there are 5 heterozygous alleles, then \(n = 5\).
- Calculate \(2^5 = 32\) gametes.

**Hint**: Remember that more heterozygous alleles lead to more gametes.

3. **Identify the Correct Option**:
After evaluating all options:
- Option A: 8 gametes
- Option B: 16 gametes (Correct)
- Option C: 8 gametes
- Option D: 32 gametes

The only option that produces 16 different gametes is **Option B**.

### Conclusion:
The individual that can produce 16 different gametes is represented by **Option B**.