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A cross is made between F(1) (that carri...

A cross is made between `F_(1)` (that carries two heterozygous pairs of alleles of tall and red) and a full double recessive combination for these two genes (dwarf and white). The expected progency will have

A

all tall and red

B

tall and red, tall and white, dwarf and white in 1:2:1 ratio

C

tall and red: dwarf and white in 1:1 ratio

D

tall and red: tall and white: dwarf and red: dwarf and white flowered plants in 1:1:1:1 ratio

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The correct Answer is:
To solve the problem, we need to analyze the genetic cross between the F1 generation, which is heterozygous for two traits (tall and red), and a double recessive parent (dwarf and white). Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Genotypes - The F1 generation is heterozygous for both traits: - Tall (T) is dominant over dwarf (t). - Red (R) is dominant over white (r). - Therefore, the genotype of the F1 plant is TtRr (heterozygous for both traits). - The double recessive parent is homozygous recessive for both traits: - Its genotype is ttrr (dwarf and white). ### Step 2: Set Up the Cross - We will perform a test cross between the F1 plant (TtRr) and the double recessive plant (ttrr). - The gametes produced by the F1 plant (TtRr) can be: - TR (Tall and Red) - Tr (Tall and White) - tR (Dwarf and Red) - tr (Dwarf and White) ### Step 3: Create a Punnett Square - We will set up a Punnett square to visualize the combinations of the gametes from the F1 plant and the double recessive parent. | | tr (ttrr) | tr (ttrr) | |-------|-----------|-----------| | **TR** | TtRr (Tall, Red) | TtRr (Tall, Red) | | **Tr** | Ttrr (Tall, White) | Ttrr (Tall, White) | | **tR** | ttRr (Dwarf, Red) | ttRr (Dwarf, Red) | | **tr** | ttrr (Dwarf, White) | ttrr (Dwarf, White) | ### Step 4: Determine the Progeny - From the Punnett square, we can see the following combinations: - 2 TtRr (Tall, Red) - 2 Ttrr (Tall, White) - 2 ttRr (Dwarf, Red) - 2 ttrr (Dwarf, White) ### Step 5: Calculate the Ratios - The expected phenotypic ratio of the progeny will be: - 2 Tall Red : 2 Tall White : 2 Dwarf Red : 2 Dwarf White - This simplifies to a ratio of 1:1:1:1. ### Conclusion The expected progeny from the cross will be: - Tall and Red - Tall and White - Dwarf and Red - Dwarf and White ### Final Answer The expected progeny will be in the ratio of 1:1:1:1 for the combinations of Tall Red, Tall White, Dwarf Red, and Dwarf White. ---

To solve the problem, we need to analyze the genetic cross between the F1 generation, which is heterozygous for two traits (tall and red), and a double recessive parent (dwarf and white). Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Genotypes - The F1 generation is heterozygous for both traits: - Tall (T) is dominant over dwarf (t). - Red (R) is dominant over white (r). - Therefore, the genotype of the F1 plant is TtRr (heterozygous for both traits). ...
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