R is dominant red flowerr trait while r is recessive white flower trait. Heterozygous Rr (red) is crossed with homozygous red flowered plant. 64 offspring are produced. Number of white flowered plants is:-

Options

A. 64
B. 32
C. 16
D. 0

Answer

To solve the problem, we need to analyze the genetic cross between the two plants based on the information given.

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parents**:
- Parent 1 (heterozygous red flower): Rr
- Parent 2 (homozygous red flower): RR

2. **Determine the Gametes Produced**:
- Parent 1 (Rr) can produce two types of gametes: R and r.
- Parent 2 (RR) can only produce one type of gamete: R.

3. **Set Up the Punnett Square**:
- We can set up a Punnett square to visualize the possible offspring from this cross.
```
R | R
----------------
R | RR | RR
----------------
r | Rr | Rr
```

4. **Analyze the Offspring**:
- From the Punnett square, we see that the possible genotypes of the offspring are:
- 2 RR (homozygous red)
- 2 Rr (heterozygous red)
- All offspring will express the red flower trait since both RR and Rr result in red flowers.

5. **Count the Number of Offspring**:
- Total offspring produced = 64
- Since all offspring are red flowered (either RR or Rr), there will be no white flowered plants.

6. **Conclusion**:
- The number of white flowered plants = 0.

### Final Answer:
The number of white flowered plants is **0**.

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