If haploid number is 10, what would be the number of monosomic and tetrasomic conditions

Options

A. 10,40
B. 19,22
C. 9,22
D. 19,40

Answer

To solve the question regarding the number of monosomic and tetrasomic conditions when the haploid number is given as 10, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Haploid Number (n)**:
- The haploid number (n) is given as 10.

2. **Calculate the Diploid Number (2n)**:
- The diploid number is calculated by multiplying the haploid number by 2.
- \( 2n = 2 \times 10 = 20 \).

3. **Determine the Monosomic Condition**:
- Monosomy is defined as having one less chromosome than the diploid number.
- The formula for monosomy is \( 2n - 1 \).
- Substituting the diploid number:
- \( 2n - 1 = 20 - 1 = 19 \).
- Therefore, the number of chromosomes in the monosomic condition is 19.

4. **Determine the Tetrasomic Condition**:
- Tetrasomy is defined as having two extra chromosomes than the diploid number.
- The formula for tetrasomy is \( 2n + 2 \).
- Substituting the diploid number:
- \( 2n + 2 = 20 + 2 = 22 \).
- Therefore, the number of chromosomes in the tetrasomic condition is 22.

5. **Final Answer**:
- The number of chromosomes in monosomic condition is 19, and in tetrasomic condition is 22.

### Summary:
- Monosomic condition: 19 chromosomes
- Tetrasomic condition: 22 chromosomes

### Answer:
The correct options are 19 and 22.

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