Frequencyof an autosomal recessive lethal gene is 0.4 Frequency of carrier in a population of 200 individuals is

Options

A. 72
B. 96
C. 104
D. 36

Explanation

To solve the problem of finding the frequency of carriers in a population of 200 individuals when the frequency of an autosomal recessive lethal gene is given as 0.4, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the frequency of the recessive allele (q)**:
- The frequency of the autosomal recessive lethal gene (q) is given as 0.4.

2. **Calculate the frequency of the dominant allele (p)**:
- Since p + q = 1, we can find p:
\[ p = 1 - q = 1 - 0.4 = 0.6 \]

3. **Use the Hardy-Weinberg principle to find the frequency of carriers**:
- The frequency of heterozygous carriers (2pq) can be calculated using the formula:
\[ 2pq = 2 \times p \times q \]
- Substituting the values of p and q:
\[ 2pq = 2 \times 0.6 \times 0.4 = 0.48 \]

4. **Calculate the number of carriers in the population**:
- To find the actual number of carriers in a population of 200 individuals, multiply the carrier frequency by the total population:
\[ \text{Number of carriers} = 0.48 \times 200 = 96 \]

5. **Conclusion**:
- Therefore, the frequency of carriers in the population of 200 individuals is 96.

### Final Answer:
The frequency of carriers in a population of 200 individuals is **96**.

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