Number of barr bodies present in turner's syndrome is

Options

A. 0
B. 1
C. 2
D. 2 or 3

Answer

To determine the number of Barr bodies present in Turner’s syndrome, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Barr Bodies**: Barr bodies are the inactivated X chromosomes in a cell. Typically, in a female with two X chromosomes, one X chromosome is inactivated, resulting in one Barr body.

2. **Identify Turner’s Syndrome**: Turner’s syndrome is a chromosomal condition that affects females, characterized by the presence of only one X chromosome (45, X instead of the usual 46 chromosomes).

3. **Determine the Number of X Chromosomes**: In Turner’s syndrome, the individual has only one X chromosome. Therefore, the total number of X chromosomes is 1.

4. **Calculate the Number of Barr Bodies**: The formula to calculate the number of Barr bodies is:
\[ \text{Number of Barr Bodies} = \text{Total number of X chromosomes} - 1 \]
In this case:
\[ \text{Number of Barr Bodies} = 1 - 1 = 0 \]

5. **Conclusion**: Since there is only one X chromosome in Turner’s syndrome, the number of Barr bodies is 0.

### Final Answer:
The number of Barr bodies present in Turner’s syndrome is **0**.

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