How many chromosomes would you find in a somatic cell of a female with webbed neck, primary amenorrhoea, small undeveloped breasts and ovaries?

Options

A. 46
B. 47
C. 44
D. 45

Answer

To determine the number of chromosomes in a somatic cell of a female with webbed neck, primary amenorrhea, small undeveloped breasts, and ovaries, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Condition**: The symptoms described (webbed neck, primary amenorrhea, small undeveloped breasts, and ovaries) are characteristic of Turner syndrome.

2. **Understand Normal Chromosome Count**: A normal female somatic cell contains 46 chromosomes, which consists of 44 autosomes and 2 sex chromosomes (XX).

3. **Chromosome Count in Turner Syndrome**: In Turner syndrome, one of the X chromosomes is missing. Therefore, instead of having two X chromosomes (XX), individuals with Turner syndrome have only one (X0).

4. **Calculate the Total Chromosomes**:
- In Turner syndrome, the total chromosome count is 45.
- This is composed of 44 autosomes and 1 sex chromosome (X0).

5. **Conclusion**: Therefore, the number of chromosomes in a somatic cell of a female with Turner syndrome is 45.

### Final Answer:
The number of chromosomes in a somatic cell of a female with Turner syndrome is **45**.

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