In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

Options

A. 0.7
B. 0.4
C. 0.5
D. 0.6

Answer

To calculate the frequency of allele A in the population, we can follow these steps:

### Step 1: Identify the genotypes and their counts
From the question, we have the following genotypes and their respective counts:
- Genotype AA: 360 individuals
- Genotype Aa: 480 individuals
- Genotype aa: 160 individuals

### Step 2: Calculate the total number of individuals
The total population is given as 1000 individuals.

### Step 3: Calculate the frequency of each genotype
- Frequency of AA (p²) = Number of AA individuals / Total individuals = 360 / 1000 = 0.36
- Frequency of Aa (2pq) = Number of Aa individuals / Total individuals = 480 / 1000 = 0.48
- Frequency of aa (q²) = Number of aa individuals / Total individuals = 160 / 1000 = 0.16

### Step 4: Calculate the frequency of allele a (q)
Since q² is the frequency of the homozygous recessive genotype (aa), we can find q by taking the square root of q²:
- q = √(q²) = √(0.16) = 0.4

### Step 5: Calculate the frequency of allele A (p)
Using the relationship p + q = 1, we can find p:
- p = 1 - q = 1 - 0.4 = 0.6

### Step 6: Conclusion
The frequency of allele A in the population is 0.6.

### Final Answer
The frequency of allele A in the population is **0.6**.

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