The genotypes of husband and wife are `I^(A)I^(B)` and `I^(A)i`. Among the blood groups of their children how many different genotypes and phenotypes are possible

Options

A. 3 genotypes , 3 phonotypes
B. 3 genotypes, 4 phenotypes
C. 4 genotypes , 3 phenotypes
D. 4 genotypes , 4 phenotypes

Answer

To solve the problem, we need to determine the possible genotypes and phenotypes of the children based on the genotypes of the parents. The genotypes of the husband and wife are `I^(A)I^(B)` and `I^(A)i`, respectively.

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parents:**
- Husband's genotype: `I^(A)I^(B)` (Blood group AB)
- Wife's genotype: `I^(A)i` (Blood group A)

2. **Determine the Gametes Produced by Each Parent:**
- The husband can produce two types of gametes: `I^(A)` and `I^(B)`.
- The wife can produce two types of gametes: `I^(A)` and `i`.

3. **Set Up a Punnett Square:**
- Create a Punnett square to visualize the combinations of gametes from both parents.
- The rows will represent the gametes from the husband, and the columns will represent the gametes from the wife.

| | `I^(A)` | `i` |
|-------|---------|-------|
| `I^(A)` | `I^(A)I^(A)` | `I^(A)i` |
| `I^(B)` | `I^(A)I^(B)` | `I^(B)i` |

4. **List the Possible Genotypes of the Children:**
- From the Punnett square, we can see the following combinations:
- `I^(A)I^(A)` (Blood group A)
- `I^(A)I^(B)` (Blood group AB)
- `I^(A)i` (Blood group A)
- `I^(B)i` (Blood group B)

5. **Identify the Unique Genotypes:**
- The unique genotypes are:
- `I^(A)I^(A)`
- `I^(A)I^(B)`
- `I^(A)i`
- `I^(B)i`
- This gives us a total of **4 different genotypes**.

6. **Identify the Phenotypes Corresponding to the Genotypes:**
- The phenotypes corresponding to the genotypes are:
- `I^(A)I^(A)` → Blood group A
- `I^(A)I^(B)` → Blood group AB
- `I^(A)i` → Blood group A
- `I^(B)i` → Blood group B
- The unique phenotypes are:
- Blood group A
- Blood group AB
- Blood group B
- This gives us a total of **3 different phenotypes**.

### Conclusion:
The final answer is that there are **4 different genotypes** and **3 different phenotypes** possible among the children.