If in a population showing sigmoid growth curve the value of K-N/K is 0.95 then what is true for this population.

Options

A. The carrying capacity has been nearly realized
B. The carrying capacity has not been substantially realized and it can accmmodate many more organisms
C. The carrying capacity is only `50%` realized
D. Data is insufficient to comment anything

Answer

To solve the question regarding the population showing a sigmoid growth curve with the value of \( \frac{K-N}{K} = 0.95 \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Variables**:
- In the logistic growth model, \( K \) represents the carrying capacity of the environment, which is the maximum population size that the environment can sustain.
- \( N \) represents the current population size.
- The expression \( \frac{K-N}{K} \) indicates how much of the carrying capacity is still available for the population to grow.

2. **Substituting the Given Value**:
- We are given that \( \frac{K-N}{K} = 0.95 \).
- This means that \( K - N = 0.95K \).

3. **Rearranging the Equation**:
- From the equation \( K - N = 0.95K \), we can rearrange it to find \( N \):
\[ N = K - 0.95K = 0.05K \]

4. **Interpreting the Result**:
- The result \( N = 0.05K \) indicates that the current population size \( N \) is only 5% of the carrying capacity \( K \).
- This implies that there is still a significant amount of capacity available for the population to grow.

5. **Conclusion**:
- Since \( N \) is much less than \( K \), the population is currently under the carrying capacity, which means it has the potential to increase significantly.
- Therefore, the population can accommodate more individuals, and it is not yet at its maximum sustainable level.

### Final Answer:
The population can accommodate more organisms, as it is currently at only 5% of its carrying capacity.