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If 50 heavy DNA (N^(15)) molecules are r...

If 50 heavy DNA `(N^(15))` molecules are replicated 2 times in `N^(14)` medium, what is obtained?

A

genotype

B

gene pool

C

gene factor

D

none of the above

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The correct Answer is:
To solve the problem of what is obtained when 50 heavy DNA (N^15) molecules are replicated two times in N^14 medium, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Initial Condition**: - We start with 50 heavy DNA molecules, which are labeled with N^15. This means that all the nitrogen bases in these DNA molecules contain the heavier isotope of nitrogen (N^15). 2. **First Replication in N^14 Medium**: - When these DNA molecules are replicated for the first time in a medium containing N^14, each original heavy DNA strand (N^15) will serve as a template for the synthesis of a new complementary strand. - The result of this replication will be: - Each of the 50 original N^15 strands will pair with a newly synthesized N^14 strand. - Thus, after the first replication, we will have 50 DNA molecules that are hybrids: each will consist of one N^15 strand and one N^14 strand. 3. **Counting the Molecules After First Replication**: - After the first replication, we have 50 hybrid DNA molecules, each containing one N^15 and one N^14 strand. 4. **Second Replication in N^14 Medium**: - Now, these 50 hybrid DNA molecules (N^15/N^14) will undergo a second round of replication in the N^14 medium. - During this replication: - Each N^15 strand will again serve as a template, producing a new N^14 strand. - Each N^14 strand from the first replication will also serve as a template, producing another N^14 strand. 5. **Counting the Molecules After Second Replication**: - After the second replication, we will have: - 50 strands that are N^15/N^14 (from the first replication) will yield 50 new strands that are N^14. - Additionally, the 50 strands that were N^14 from the first replication will also yield 50 new strands that are N^14. - Therefore, the final count of DNA molecules will be: - 50 hybrid (N^15/N^14) and 100 N^14 strands. 6. **Final Composition**: - In total, after two rounds of replication, we will have: - 50 DNA molecules with one N^15 and one N^14 strand (hybrid). - 100 DNA molecules with both strands as N^14. ### Conclusion: The final result of replicating 50 heavy DNA (N^15) molecules two times in N^14 medium will yield a mixture of DNA molecules: - 50 hybrid molecules (N^15/N^14) - 100 molecules with both strands as N^14.
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