There are 125 amino acids. We want to synthesize an mRNA. How many nitrogen bases are required to form sufficient codons to code all 125 amino acids?

Options

A. 375
B. 125
C. 42
D. 3

Answer

To determine how many nitrogen bases are required to form sufficient codons to code for 125 amino acids, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Codons**: A codon is a sequence of three nitrogen bases (nucleotides) in mRNA that corresponds to a specific amino acid.

2. **Calculating the Number of Codons Needed**: Since each amino acid is coded by one codon, and we have 125 amino acids, we will need 125 codons.

3. **Calculating the Total Number of Nitrogen Bases**: Each codon consists of 3 nitrogen bases. Therefore, to find the total number of nitrogen bases required, we multiply the number of codons by the number of bases per codon:
\[ \text{Total nitrogen bases} = \text{Number of codons} \times \text{Bases per codon} = 125 \times 3 \]

4. **Performing the Calculation**:
\[ 125 \times 3 = 375 \]

5. **Conclusion**: Thus, a total of 375 nitrogen bases are required to code for 125 amino acids.

### Final Answer:
The total number of nitrogen bases required to form sufficient codons to code for all 125 amino acids is **375**.

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