15 gm of a substance dissolved in 450 gms of water produces a depression of `-0.34^@` C in the freezing point . Calulation the Mol. Wt. of the solid ( `K_f` for water is 1.86 K kg ` mol ^(-1)`)

Explanation

`Delta T_f =K_f xx w/M xx 100/W` < br> `implies12 =18.5xx15/Mxx100/ 150`
`implies M = (18.5xx15xx100)/(1.2xx150)`
`= 154.16 gm mol^(-1)`