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If Mg^(2+) +2e rarrMg(s), E=-2.37 V, Cu...

If `Mg^(2+) +2e rarrMg(s), E=-2.37 V, Cu^(2+) + 2e rarrCu(s),E=+0.34V` then the emf of the cell `Mg|Mg^(+2)||Cu^(2+)|Cu` is :

A

`2.71V`

B

`2.30V`

C

`2.80V`

D

`1.46V`

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The correct Answer is:
A
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