Home
Class 12
CHEMISTRY
Deduce from the following E^@ values of...

Deduce from the following `E^@` values of half cells, what combination of two halt would resutlt in a cell with the largenst potential :
(i)` A+e rarr A ,E^@=-0.24V`
(ii) `B^- +e rarrB^(2-),E^@=+1.25V`
(iii) `C^- +2erarrC^(3-),E^@=-1.25V`
(iv) `D + 2e rarrD^(2-), E^@=+ 0.68V`

A

`(ii) and (iii)`

B

`(ii) and (iv)`

C

`(i) and (iii)`

D

`(i) and (iv)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    MBD PUBLICATION|Exercise QUESTION BANK|914 Videos

  • ENVIRONMENTAL CHEMISTRY

    MBD PUBLICATION|Exercise QUESTION BANK|299 Videos

Similar Questions

Explore conceptually related problems

Deduce from the following E^@ values of half cells, what combination of two halt would resutlt in a cell with the largenst potential : (i) Ararr A^+ +e ,E^@=+1.2V (ii) B^-rarrB+e,E^@=-2.1V (iii) CrarrC^(2+) +2e,E^@=-0.38V (iv) D^(2-) rarrD^- +e,E^@=-0.59V

Deduce from the following E^@ values of half cells , what combination of two half cells would result in a cell with largest potential : (i) A^(3-) rarr A^(2-) + e^- , E^@=1.5 V (ii) B^(2+) +e^- rarrB^+ ,E^@ =-2.1V (iii) C^(2+)+e^- rarrC^+,E^@=+0.5V (iv) DrarrD^2 +2e^-,E^@=-1.5V

Consider the standard potential of the following cells, (i) Mg^(2+) +2e rarr Mg,E^@=-2.37V (ii) Zn^(2+) + 2erarrZn,E^@ =-0.76V (iii) Ni^(2+) +2e rarrNi,E^@=-0.25V (iv) Fe^(3+) + 3e rarrFe, E_0=-0.04 V find the strongest reducing agent :

Given electrode potentials are: Fe^(3+) +e rarrFe^(2+) ,E^@=0.771V I_2 +2e rarr 2I^- ,E^@=0.536V E^@ cell for the cell reaction, 2Fe^(3+) +2I^- rarr2Fe(2+) +I_2 is:

The standard reduction potential at 290K for the following half reactions are, (i) Zn^(2+) +2e rarrZn(s),E^@ =-0.762 V (ii) Cr^(3+) +3e rarr Cr(s), E^@=-0.740 V (iii) 2H^+ 2e rarrH_2(g),E^@=-0.000V (iv) Fe^(3+) +e rarr Fe^2+,E^@=+0.77V Which it the strongest reducing agent :

MBD PUBLICATION-ELECTROCHEMISTRY-QUESTION BANK
  1. The standard oxidation potentials, E^@ for the half reactions are : Z...

    Text Solution

    |

  2. The solution of CuSO4in which copper rod is immersed is diluted to 10 ...

    Text Solution

    |

  3. Deduce from the following E^@ values of half cells, what combination ...

    Text Solution

    |

  4. Deduce from the following E^@ values of half cells, what combination ...

    Text Solution

    |

  5. Deduce from the following E^@ values of half cells , what combination ...

    Text Solution

    |

  6. E^@ for F2 +2erarr 2F^- is 2.8V,E^@ for 1//2F2+erarr F^- is :

    Text Solution

    |

  7. For the cell ,Tl |Tl^+(0.001M)|| Cu,E(cell) at 25^@ C is 0.83V.E(cell)...

    Text Solution

    |

  8. How much will the reduction potential of a hydrogen electrode change w...

    Text Solution

    |

  9. The charge for the reduction of 1 mole of Cr2O7^(2-) ions to Cr^(3+) i...

    Text Solution

    |

  10. 10800 C of electricity on passing through the electrolyte solution dep...

    Text Solution

    |

  11. I coulomb of charge passes through solution of AgNO3 and CuSO4 connect...

    Text Solution

    |

  12. During electrolysis of H2O , the molar ratio of H2 and O2 formed is:

    Text Solution

    |

  13. On passing 3 faraday of electricity through the three electrolytic cel...

    Text Solution

    |

  14. The weight of silver (eq.wt,=108)displaced by that quanitiy of current...

    Text Solution

    |

  15. The volume of oxygen at NTP Liberated by 5 ampere current flowing for ...

    Text Solution

    |

  16. Salts of A (atomic weight 7), B (atomic weight 27) and C (atomic weigh...

    Text Solution

    |

  17. To produce 160 g of oxygen, the number of mole of water required to be...

    Text Solution

    |

  18. The weight of nickel (at .wt. =58.7) liberated by a current of 5 amper...

    Text Solution

    |

  19. Electrolytes when dissolved in water dissociate into ions, because :

    Text Solution

    |

  20. The metal that cannot be produced on reduction of is oxide by aluminiu...

    Text Solution

    |