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A 1st order reaction is 20% complete in ...

A 1st order reaction is `20%` complete in 20 minutes. Calculate the time it will take the reaction to complete `80%`.

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`K=2.303/t"log"[A]_0/[A]=2.303/20log)[A]_0/[(80/100)[A]_0] =2.303/20"log"(5/4)=2.303/20xx0.0969=0.011min^-1`
Now ,`t=2.303/20"log"[A]_0/[A]impliest=2.303/0.011xxlog5=2.303/0.011xx0.699=144.2min.`
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