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For the decomposition of N2O5(g), it is ...

For the decomposition of `N_2O_5(g)`, it is given that :`2N_2O_5(g)rarr4NO_2(g)+O_2(g)`,Activation energy `E_aN_2O_5(g)rarr2NO_2(g)+(1/2)O_2(g)`,Activation energy`E_a`then:

A

`E_a=E_a`

B

`E_agtE_a`

C

`E_altE_a`

D

`E_a=2E_a`

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The correct Answer is:
A
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For the decomposition of N_(2) O_(5) given as, N_(2) O_(5) (g) to N_(2) O_(4) (g) + 1//2O_(2) (g) If the rate law =K [N_(2) O_(5) ] and K=1.68 xx 10^(-2)" s"^(-1) , starting with 2.5 moles, of N_(2) O_(5)(g) in a 5.0"L" container at 298K, how many moles of N_(2) O_(5) would remain after 1.0 minutes?

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