Home
Class 12
CHEMISTRY
A complex of cobalt has five ammonia mol...

A complex of cobalt has five ammonia molecules, one nitro group and two chlorine atoms for each cobalt atom. One mole of this compound produces three mole ions in aqueous solution which on treating with excess of `AgNO_3` give two mole of AgCl. The formula of the compound is

A

`[Co(NH_3)_4NO_2CI][(NH_3)CI]`

B

`[Co(NH_3)_5CI][CINO_2]`

C

`[Co(NH_3)_5NO_2]CI_2`

D

`[Co(NH_3)_5][(NO_2)_2CI_2]`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    MBD PUBLICATION|Exercise QUESTION BANK|204 Videos

  • ELECTROCHEMISTRY

    MBD PUBLICATION|Exercise QUESTION BANK|1030 Videos

Similar Questions

Explore conceptually related problems

One mole of complex compound Co (NH_3)_5 Cl_3 gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO_3 solution to yield two moles of Ag Cl _(s) , The structure of the complex is

An aldehyde A(C_(11)H_(8)O) which does not undergo self aldol condensation but gives benzaldehyde and two moles of B on ozonolysis. Compound B on oxidation with silver ions gives oxalic acid. Identify compound A and B.

Give the formula of each of the following coordination entities. Co^(3+) ion is bound to one Cl^(-) , one NH_(3) molecule and two bidentate ethylenediammine (en) molecules.

PtCl_(4)andNH_(3) may form five complexes, A (PtCl_(4)*6NH_(3)),B(PtCl_(4)*5NH_(3)),C(PtCl_(4)*4NH_(3)),D(PtCl_(4)*3NH_(3))andE(PtCl_(4)*2NH_(3)) . One mole of each A, B, C, D and E reacts with excess of AgNO_(3) to yield 4, 3, 2 and 1 mole(s) of AgCl respectively, while E gives, no AgCl. The conductance of their solutions are in the order AgtBgtCgtDgtE . On the basis of Werner's theory, write their strucutre and give the total number of ions given by one complex.