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The cartesian equation of a line is (x-5...

The cartesian equation of a line is `(x-5)/(3)=(y+4)/(7)=(z-6)/(2)`.Write its vector form.

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The correct Answer is:
`therefore vecr=(5hati-4hatj+6hatk)+lambda(3hati+7hatj+2hatk)`
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KUMAR PRAKASHAN-THREE DIMENSIONAL GEOMETRY-EXERCISE-11.2
  1. Show that the three lines with direction cosines (12)/(13),(-3)/(13),(...

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  2. Show that the line passing through (1, -1, 2) and (3, 4, -2) is perpen...

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  3. Show that the line passing through the points (4, 7, 8) and (2, 3, 4) ...

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  4. Find the equation of the line which passes through the point (1, 2, 3)...

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  5. Find the equation of the line in vector and in cartesian form that pas...

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  6. Find the cartesian equation of the line which passes through the point...

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  7. The cartesian equation of a line is (x-5)/(3)=(y+4)/(7)=(z-6)/(2).Writ...

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  8. Find the vector and the cartesian equations of the lines that passes t...

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  9. Find the vector and the cartesian equations of the line that passes th...

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  10. Find the angle between the following pairs of lines : (i) vecr=2ha...

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  11. Find the angle between the following pair of lines : (i) (x-2)/(2)...

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  12. Find the values of p so that the lines (1-x)/(3)=(7y-14)/(2p)=(z-3...

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  13. Show that the lines (x-5)/(7)=(y+2)/(-5)=z/1 and x/1=y/2=z/3 are perpe...

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  14. Find the shortest distance between the lines vecr=(hati+2hatj+hatk...

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  15. Find the shortest distance between the lines (x+1)/(7)=(y+1)/(-6)=(...

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  16. Find the shortest distance between the lines whose vector equations ar...

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  17. Find the shortest distance between the lines whose vector equations ar...

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