Home
Class 12
MATHS
The cartesian equations of a line are 3x...

The cartesian equations of a line are 3x + 1 = 6y - 2 = 1 - z. Find the fixed point through which it passes, its direction ratios and also its vector equation.

Text Solution

Verified by Experts

The correct Answer is:
`(-1/3,1/3,1):2,1,-6`
`vecr=-1/3hati+1/3hatj+hatk+lambda(2hati+hatj-6hatk)`
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    KUMAR PRAKASHAN|Exercise TEXTBOOK IILUSTRATIONS FOR PARCTICE WORK|30 Videos
  • THREE DIMENSIONAL GEOMETRY

    KUMAR PRAKASHAN|Exercise SOLUTION OF NCERT EXAMPLAR PROBLEMS (Short Answer Type Question)|49 Videos
  • THREE DIMENSIONAL GEOMETRY

    KUMAR PRAKASHAN|Exercise MISCELLANEOUS EXERCISE-11|23 Videos
  • RELATIONS AND FUNCTIONS

    KUMAR PRAKASHAN|Exercise Practice Paper - 1 (Section - D)|2 Videos
  • VECTOR ALGEBRA

    KUMAR PRAKASHAN|Exercise Practice Paper - 10 (Section-D)|2 Videos

Similar Questions

Explore conceptually related problems

The cartesian equation of a line are 6x - 2 = 3y + 1 = 2z - 2. Find its vector equation.

The cartesian equation of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find the vector of the line.

The cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.

The cartesian equation of the line passing through (4, 9, 8) and (3, - 2, 1) is ..

The Cartesian equation of a line is (x+3)/(2)=(y-5)/(4)=(z+6)/(2) Find the vector equation for the line.

The cartesian equation of a line is (x-5)/(3)=(y+4)/(7)=(z-6)/(2) .Write its vector form.

Find equation of the line parallel to the line 3x-4y+2=0 and passing through the point (-2,3) .

The cartesian equations of the plane perpendicular to the line (x-1)/(2)=(y-3)/(-1)=(z-4)/(2) and passing through the origin is

KUMAR PRAKASHAN-THREE DIMENSIONAL GEOMETRY-PRACTICE WORK
  1. Find the direction cosines of the line (x-2)/(2)=(2y-5)/(-3),z=-1. Als...

    Text Solution

    |

  2. If the points A(-1, 3, 2), B(-4, 2, -2) and C(5, 5, lambda) are collin...

    Text Solution

    |

  3. The cartesian equations of a line are 3x + 1 = 6y - 2 = 1 - z. Find th...

    Text Solution

    |

  4. Find the vector equation of a line passing| through (2, -1, 1) and par...

    Text Solution

    |

  5. squareABCD is a parallelogram. The position vectors of the points A, B...

    Text Solution

    |

  6. Find the coordinates of the point where the line through (5, 1, 6) and...

    Text Solution

    |

  7. Find the angle between the lines vecr = (3 + lambda)hati + 2(1 + l...

    Text Solution

    |

  8. Find the angle between the lines whose direction cosines are given by ...

    Text Solution

    |

  9. Show that the lines (x-2)/(3)=(y+1)/(-2)=2 and (x-1)/(1)=(2y+3)/(3)=(z...

    Text Solution

    |

  10. Prove that if the lines x = ay + b, z = cy + d and x = a'y + b', z = c...

    Text Solution

    |

  11. Find the values of p so that the lines (1-x)/(3)=(7y-14)/(2p)=(z-3...

    Text Solution

    |

  12. Find the shortest distance between the lines vecr =(8+3lambda) hati - ...

    Text Solution

    |

  13. Find the shortest distance between the lines vecr=(4hati-hatj)+lam...

    Text Solution

    |

  14. Find the shortest distance between the lines (x-1)/(2)=(y-2)/(3)=(...

    Text Solution

    |

  15. Find the shortest distance between the lines vecr=(lambda-1)hati+(...

    Text Solution

    |

  16. Find the direction cosines of perpendicular from the origin to the pla...

    Text Solution

    |

  17. Find the vector equation of a plane which is at a distance 11 units fr...

    Text Solution

    |

  18. Find the vector equation of the plane vecr=hati-hatj+lambda(hati+hatj+...

    Text Solution

    |

  19. Find the cartesian equation of the plane through the point (2,-1, 1) a...

    Text Solution

    |

  20. Find the vector equation of the plane passing through the points (1, -...

    Text Solution

    |