Find the distance of a point (2, 5, -3) ...

Find the distance of a point (2, 5, -3) from the plane `vecr.(6hati-3hatj+2hatk)=4`

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The correct Answer is:

`(13)/(7)`

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Find the equation of the plane passing through (a, b, c) and parallel to the plane vecr.(hati+hatj+hatk)=2 .

Find the direction cosines of perpendicular from the origin to the plane vecr.(6hati-3hatj-2hatk)+1=0 .

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+3hatj-hatk)=0 and vecr.(hatj+2hatk)=0 and also passing through the point 2hati+hatj-hatk .

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Find the equation of the plane which contains the line of intersection of the planes vecr.(hati+2hatj+3hatk)-4=0,vecr.(2hati+hatj-hatk)+5=0 and which is perpendicular to the plane vecr.(5hati+3hatj-6hatk)+8=0

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