Moment of inertia of a disc about the axis of rotation is` 10 kgm^2`. A constant torque of 50 Nm acts on it. Find :Angular velocity at the end of 10s, if the disc is initially at rest.

Moment of inertia of a disc about the axis of rotation is 10 kgm^2 . A constant torque of 50 Nm acts on it. Find :Angular acceleration .

The moment of inertia of a disc about a tangent axis in its plane is

The moment if inertia of the earth about its axis of rotation is 9.83 xx 10^37 kgm^2 and if its angular velocity is 7.3 xx 10^-5 rad s^-1 . Calculate Radius of gyration

The moment of inertia of flywheel is 4 kg m^2 . If a torque of 10 Nm is applied on it, then the angular acceleration produced will be

A disc of moment of inertia 3 kg m^2 is acted upon by a constant torque of 60 Nm, if the disc is at rest, then the time after which the angular velocity of the disc is 90 rad/s, will be

A disc rotates horizontal at the rate of 100 rpm and M.I. of the disc about the axis of rotation is 1 kg m^2 . If a blob of molten wax weighing 50 gm drops gently at a distance 20 cm from the axis of rotation of the disc and remains stuck to it, then the increase in moment of inertia of the system will be

The moment if inertia of the earth about its axis of rotation is 9.83 xx 10^37 kgm^2 and if its angular velocity is 7.3 xx 10^-5 rad s^-1 . Calculate Kinetic Energy of rotation.

A torque of 50 Nm acts on a rotating body for 5 s. Its angular momentum

The moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane 'I'. It is rotating with angular velocity 'omega'. Another identical ring is gently placed on it so that their centres coincide. If both the rings are rotating about the same axis then loss in kinetic energy is

The moment of inertia of uniform circular disc about an axis passing through its centre is 6 kgm^2 . Its M. I. about an axis perpendicular to its Plane and just touching the rim will be