A metallic ring of a mass 1kg has moment of Inertia `1kgm^2` when rotating about one of its diameters. It is molten remolded into a thin uniform disc of the same radius. Find M.I. about central axis of uniform disc perpendicular to plane.

A metallic ring of mass 1 kg has moment of inertia 1 kg m^2 when rotating about one of its diameters. It is molten and remolded into a thin uniform disc of the same Radius. How much will its moment of inertia be, when rotated about its own axis.

A metallic ring of mass 1 kg has moment of inertia 1kg m2 when rotating about one of its diameters. It is molten and remoulded into a thin uniform disc of the same radius. H ow much will its moment of inertia be, when rotated about its own axis.

State an expression for moment inertia of a thin uniform disc about an axis passing through its centre and perpendicular to its plane .

The moment of inertia of a ring about one of its diameters is 2 kg m^2 . What will be its moment of inertia about a tangent parallel to the diameter ?

Moment of inertia of a thin uniform rod about an axis passing through one end and perpendicular to its length is I . Then moment of inertia of the same rod about the central axis perpendicular to its plane is

The moment of inertia of a thin circular disc of mass M and radius R about any diameter is

Two rings of the same mass and radius are placed such that their centers are at a common point and, their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the diameter of one of the rings is I.Then moment of inertia of one of the rings of the system' about the central axis and perpendicular to its plane would be

If the diameter of flywheel is increased by 1%, then increase in its M.I. about an axis passing through centre and perpendicular to the plane will be

Moment of inertia of a uniform ring about its diameter is I. Then its moment of inertia about axis passing through its centre and perpendicular to its plane is