Show that for pipe closed at one end, the end correction is e= `(n_1l_1-n_2l_2)/(n_2-n_1)` where, the symbols have their usual meaning.

Two organ pipes open at both ends have same diameter but different lengths. Show that end correction at each end is e= (n_1l_1-n_2l_2) / 2(n_2-n_1) where,the symbols have their usual meaning.

Show that a + r +1=1 where symbols have their usual meaning.

State the law of radioactive decay. Hence derive the expression N = N_0(e^-lamda t) .lf where symbols have their usual meanings.

Show that σ = \(\frac{ne^2\tau}{m}\). Where symbols have usual meanings.

The frequency of vibration of air column in a pipe closed at one end is n_(1) and that of the one closed at both end is n_(2) . When both the pipes are joined to form a pipe closed atone end, the frequency of vibration of air column in it is (neglecting end correction )

An open pipe is resonance is its 2^(nd) harmonic with tuning fork of freqency f_(1) . Now it is closed at one end. If the frequency of the tuning fork is increases slowly from f_(1) , then agaain a resonance is obtained with a_(1) frequency f_(2) . if in this case the pipe vibrates n^(th) harmonics, then

Prove that a pipe open at both end of length of 2L , has same fundamental frequency as another pipe of closed at one end of length L.

The coefficient of x^n in the expansion of (1+x)^(2n) and (1+x)^(2n-1) are in the ratio.

The equation , E_1/E_2 = (l_1 + l_2)/(l_1 - l_2) is used to compare emfs of two cells by

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has//have the same energy lists: 1. n = 4, l = 2, m_l = -2 , m_s = - 1//2 2. n = 3, l = 2, m_l = 1, m_s = +1//2 3. n = 4, l = 1, m_l = 0, m_s = + 1//2 4. n = 3, l = 2, m_l = -2 , m_s = -1//2 5. n = 4, l = 1, m_l = 0 , m_s = +1//2