A metal plate is introduced between the plates of a charged parallel plate capacitor. What is its effect on the capacitance of the capacitor?

Explain in brief, the parallel plate capacitor.

A metal foil of negligible thickness is introduced between the two plates of a capacitor at the centre. The capacitance of capacitor will be

An electric field of 3 X 10^4 Vm^-1 is produced between the plates 0.05m apart, of a parallel plate capacitor when it is fully charged. Now an uncharged metal plate of thickness 0.01m is inserted between capacitor plates:- Find the potential difference after introduction of plates.

Two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3mm is introduced between the plates with the faces parallel to them. The distance between the faces is so adjusted that the capacitance of the capacitor becomes 2/3 of its original value. What is the new distance between the plates ?

What is the area of the plates of a 2 F parallel plate capacitor,given that the separation between the plates is 0.5 cm ?

If q is a charge on the capacitor and C is a capacitance, then energy stored in capacitor is

What is net charge on a charged capacitor?

On what factors does the capacitance of a parallel plate capacitor depend ?

An electric field of 3X10^4 Vm^-1 is produced between the plates 0.05m apart, of a parallel plate capacitor when it is fully charged. Now an uncharged metal plate of thickness 0.01m is inserted between capacitor plates:-What would be the potential difference if a dielectric slab (k = 3) were introduced in place of metal plate

A parallel plate capacitor with air between the plates has a capacitance of 8 pF.What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constants 6 ?