In a capacitor of capacitance `20muF`, the distance between the plates is 2 mm. If a dielectric slab of width 1 mm and dielectric constant 2 is inserted between the plates, what is the new capacitance?

A charged parallel plate capacitor has a potential energy U. if a slab of dielectric constant k is inserted between the plates, then the new potential energy will be_

The capacity of a capacitor becomes 20muF when gap between the capacitor is filled completely by a dielectric slab of k = 4. What is the capacity of a capacitor with air in between the plates?

An air capacitor of capacity 50 mu F is charged to a potential of 200 V. The area of each plate is 20 cm^2 and the distance of separation between the plates is 0.1 mm, find the energy per unit volume of the electric field between the plates of the capacitor .

Capacity of an air capacitoris 20muF .Theseparation between the parallel plates is8mm.Acopper plate of 4mm thickness is introduced symmetrically between the plates. The capacitance now becomes_

A parallel plate air condenser has a capacity of 21 mu F . What will be the new capacity if A marble slab of dielectric constant 8 is introduced between the two plates?

In a parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^-3 m^2 and the separation between the plates is 2 mm. How would charge on the plates be affected if a 2 mm thick mica sheet of k = 6 is inserted between the plates while the voltage supply remains connected ?

Explain what would happen if in the capacitor given, a 3mm thick mica sheet (of dielectric constant= 6) were inserted between the plates. After the supply was disconnected .

A parallel plate capacitor consists of two identical metal plates. Two dielectric slabs having dielectric donstants k_1 and k_2 are introduced in the space between two plates as shown below. Show that capacity of capacitor in arrangement (a) is given by , C = (epsilon_0 (k_1+k_2)A)/(2d)