The capacity of a capacitor becomes `20muF` when gap between the capacitor is filled completely by a dielectric slab of k = 4. What is the capacity of a capacitor with air in between the plates?

In a capacitor of capacitance 20muF , the distance between the plates is 2 mm. If a dielectric slab of width 1 mm and dielectric constant 2 is inserted between the plates, what is the new capacitance?

A parallel plate air condenser has a capacity of 20 mu F . What will be the new capacity if the distance between two plates is doubled ?

The force of repulsion between two identical positive charges when kept with aseparation r in air is F. half the gap between the two charges is filled by a dielectric slab of dielectric constant = 4. thenthe new force of repulsion between those two charges becomes

Derive an expression for capacitance of a parallel plate capacitor without a dielectric slab between the plates.

Two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3mm is introduced between the plates with the faces parallel to them. The distance between the faces is so adjusted that the capacitance of the capacitor becomes 2/3 of its original value. What is the new distance between the plates ?

Capacity of an air capacitoris 20muF .Theseparation between the parallel plates is8mm.Acopper plate of 4mm thickness is introduced symmetrically between the plates. The capacitance now becomes_

The capacity of a parallel plate air capacitor is 10 mu F and it is given a charge of 40 mu C . The electrical energy stored in the capacitor is

Give the expression for capacitance of a capacitor when n dielectric slabs of thickness t_1, t_2 ... t_n and dielectric constants k_1, k_2 ... k_n respectively, fills the entire space between the plates.