The capacity of a parallel plate air condenser is `8 muF`. When air is replaced by another material, its capacity becomes `16muF`. Calculate the dielectric constant of other material.

The capacity of a parallel plate condenser with dielectric constant 10 is 12 mu F . What will be its capacity if dielectric is removed ?

The capacity of a parallel plate condenser increases four times if the air between the plates is replaced by glass. The permittivity of glass will be

A parallel plate air condenser has a capacity of 21 mu F . What will be the new capacity if A marble slab of dielectric constant 8 is introduced between the two plates?

Derive an expression for capacity of a parallel plate condenser filled with dielectric

The capacity of a parallel plate air capacitor is 10 mu F and it is given a charge of 40 mu C . The electrical energy stored in the capacitor is

A parallel plate air condenser has a capacity of 20 mu F . What will be the new capacity if the distance between two plates is doubled ?

A slab of material of dielectric constant k has the same area A as the plates of a parallel plate capacitor and has thickness (3d//4) , where d is separation of the plates.The charge in capacitance when the slab is inserted between the plates is

A parallel plate condenser with air as dielectric has capacity C_0 = (in_0 A)/(d) . A thin mica sheet of dielectric constant K and thickness is introduce near the first plate and then moved with constant velocity v towards the other plate . The capacity of the condenser will be

A parallel plate capacitor with air between the plates has a capacitance of 8 pF.What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constants 6 ?

The capacity of a capacitor becomes 20muF when gap between the capacitor is filled completely by a dielectric slab of k = 4. What is the capacity of a capacitor with air in between the plates?